Calculate the binding energy per nucleon of the helium nucleus 52he. express your answer in millions of electron volts to four significant figures.

The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for 52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=binding energy
52He> 2 x 11p + 3 x10n is the equation bilan
so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
                                                        mn=mass of neutron=1.67 10^-27 kg
                                                        m nucleus= 5
Dm= 2x1.67 10^-27 kg+ 3x1.67 10^-27 kg-5=  - 4.9 J
Eb=  - 4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so -9.10^16 J/ 1.6 10^-19=  -5.625 10^35 eV

the final answer is Eb /nucleon =  -5.625 x10^35 eV

Arise 8 run 1 this means go 8 up and 1 across, which is steepest