Aspring with a constant of 120 n/m stretches by 0.02 m. what is the potential energy of the spring

Potential energy of the spring is 0.024 Joules.

Explanation:

It is given that,

Spring constant of the spring, k = 120 N/m

The spring is stretched by 0.02 m

We have to find the potential energy of the spring. Mathematically, it is given by :

Putting the values of k and x in above equation we get :

PE = 0.024 J

Hence, the potential energy of the spring is 0.024 J

it about 600 mph from what i calculated

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂