Physics, 26.01.2020 07:31, richiearieona1012

The density of aluminum is 2.7 g/cm3. a metal sample has a mass of 52.0 grams and a volume of 17.1 cubic centimeters. could the sample be aluminum

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No; the sample could not be aluminum;
since the density of aluminum, " 2.7 g/cm³ " , is NOT close enough to the density of the sample, " 3.04 g/cm³ " .

Explanation:

Density is expressed as "mass per unit volume" ;

in which:
"mass, "m", is expressed in units of "g" (grams); and:
"Volume, "V", is expressed in units of "cm³ " (such as in this problem); or in units of "mL" ;

{Note the exact conversion: " 1 cm³ = 1 mL " .}.

The formula for density: D = m/V ;

Given: The density of aluminum is: 2.7 g/cm³.

Given: A sample has a mass of 52.0 g ; and Volume of 17.1 cm³ ; could it be aluminum?

Let us divide the mass of the sample by the volume of the sample;
by using the formula:

D = m / V ;

and see if the value is at, or very close to "2.7 g/cm³ ".

If it is, then it could be aluminum.

The density for the sample:

D = (52.0 / 17.1) g/cm³ = 3.0409356725146199 g/cm³ ;
→round to "3 significant figures" ;
= 3.04 g/cm³ .

No; the sample could not be aluminum; since the density of aluminum,
"2.7 g/cm³ " is NOT close enough to the density of the sample,
"3.04 g/cm³ " .

answered: Guest

b) phosphorus pentoxide

answered: Guest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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The density of aluminum is 2.7 g/cm3. a metal sample has a mass of 52.0 grams and a volume of 17.1 c...