Three resistors of 10.0 w, 20.0 w, and 25.0 w are connected in parallel across a 100-v battery. what is the equivalent resistance of the circuit and the current flowing through the 10.0-w resistor?

In a parallel connection, the equivalent resistance is the summation of the inverse of each individual resistances. It is mathematically expressed as 1/ Req = 1/10 +1/20 + 1/25 = 5.263 ohms. Also, the voltage across each resistor is equal to the input voltage, therefore I = 100 / 10 = 10 Amps. I hope this helped you.