Acertain machine changes a large input force into a smaller output force. how will the machine affect the distance over which the force is applied? explain.

For the answer to the question above, if your question is a lever with a pivot and which sounds more likely ...then I would say from the principle of moments: F1*d1=F2*d2 

given F1=high and F2=low ---> d1 must be low and d2 high for the equations to be balanced. 

So the answer is simply: Inversely

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero.