A0.22 kg air track glider moving at 0.60 m/s a collides elastically into a 0.44 kg glider at rest. after collision the 0.22 kg glider is moving with velocity -0.20 ms. what is the speed of the 0.44 kg glider after collision

The glider collides elastically  an another glider at rest, in this case we have the coservation of quantity of movement 

m1 v1  + m2 v2 = m1V1 + m2 V2
v is the velocity before the shock, V the velocity after the shock
m1=0.22
v1=0.60m/s
m2=0.44
V1=-0.20m/s
remark that 0.44 kg glider is initially at rest, so v2= 0
the equation above can be written  m1 v1  = m1V1 + m2 V2 ( because v2=0 at rest)
m1 v1  = m1V1 + m2 V2 implies  V2= (m1v1 -m1V1) / m2

V2=0.22x0.60 -0.22x (-0.20) ] / 0.44= 0.4m/s