An electron has an initial velocity of 6.00 ✕ 106 m/s in a uniform 1.00 ✕ 105 n/c strength electric field. the field accelerates the electron in the direction opposite to its initial velocity.
(b) how far does the electron travel before coming to rest?
m
(c) how long does it take the electron to come to rest?
s
(d) what is the electron's speed when it returns to its starting point?
m/s

When seismic waves hit a fault, the waves are reflected off the fault. seismograph can detect these reflected seismic waves. geologists then use these data to map the fault's length and depth

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Ibelieve the answer is d. densityhope my answer has you : )