Physics, 05.10.2019 09:50, khandon4970

This type of heat transfer occurs when heat moves from one molecule to another.

conduction
convection
radiation

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answered: kristofwr3444

The method of transfer of heat from one molecule to the often is termed as the radiation.

Explanation:

The heat transfer between the two bodies or two molecules take place using three basic methods of the heat transfer.

The Conduction is the method of transfer of heat from one body to another body or one molecule to another molecule when they are in contact with one another. It occurs in solids because the molecules of a solid are so close to each other that they almost touch each other.

The Convection is the process of heat transfer in the molecules when the bodies are not physically touching one another. The process of convection occurs in case of the liquid in which the molecules gain heat from the source and move away and let other molecule to be heated up.

The Radiation is process of transfer of heat from one molecule to the another without any physical contact between the molecules. The radiation is the process of heat transfer from one molecule to another by means of electromagnetic radiations.

Thus, The method of transfer of heat from one molecule to the often is termed as the radiation.

Learn More:

1. The volume of gas increased if it is heated from 30 C to 300 C

2. The energy calculated in heat exchange in calorimetry

3. Amount of heat required to raise the temperature of copper

Answer Details:

Grade: High School

Subject: Physics

Chapter: Heat Transfer

Keywords:

heat transfer, conduction, convection, radiation, molecule, energy, physical contact, electromagnetic, touching.

answered: Guest

Hello how was your day? ? i hope it was good

answered: Guest

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge, $v = \dfrac{e_p}{q}$ then the following gives us the potential difference, $\delta v = v_b - v_a$ $\begin{aligned} \delta v & = \dfrac{e_p_b}{q} - \dfrac{e_p_a}{q} \\ & = \dfrac{\delta e_p}{q} \end{aligned}$ the formula $\delta v = \delta e_p / q$ may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get $\delta e_p = q\delta v$ using q = 8.00 × 10⁻¹⁹ c and δv = 2.00 v, we get $\begin{aligned} \delta e_p & = (8.00\times10^{-19} \text{ c})(2.00\text{ v}) \\ & = 1.60\times 10^{-18}\text{ j} \end{aligned}$ the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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This type of heat transfer occurs when heat moves from one molecule to another.

conducti...