Afootball is kicked straight up in the air , it hits the ground 5.6 s later. what was the greatest height kicked reached by the ball? assume it was kicked at ground level.

38.5 m

Explanation:

1) Flight time = 5.6 s (given)

2) Ascending time = fligth time / 2 = 5.6s / 2 = 2.8 s

3) Vf = Vo - gt

Hmax ⇒ Vf = 0

⇒ 0 = Vo - gt ⇒ Vo = gt = 9.81m/s² (2.8s) = 27.5 m/s

4) H = Vot - gt² / 2

⇒ H = 27.5m/s(2.8s) - 9.81m/s² (2.8s)² / 2 = 77m - 38.5m = 38.5m

38.5m

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  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂