A0.012kg rubber bullet travels at a velocity of 150m/s, hits a stationary 8.5kg concrete block resting on a frictionless surface, and ricochets in the opposite direction worth a velocity of -100m/s. how fast will the concrete block be moving?

The velocity of concrete block is 0.353 m/s

Explanation:

To calculate the velocity of the concrete block after the collision, we use the equation of law of conservation of momentum, which is:

where,

= mass of rubber bullet = 0.012 kg

= Initial velocity of rubber bullet = 150 m/s

= Final velocity of rubber bullet = -100 m/s

= mass of concrete block = 8.5 kg

= Initial velocity of concrete block = 0 m/s

= Final velocity of concrete block = ?

Putting values in above equation, we get:

Hence, the velocity of concrete block is 0.353 m/s

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

because if the tool that you are using is not balanced it there would be false mass.