If a 2 kg ball traveling at 10 m/s hits a wall and stops in 0.03 seconds, then how much force will the ball experience?

Newton's second law is:
F=m*a,

where a=dv/dt, so

F=m*(dv/dt)

Rearranging gives:
F*dt=m*dv.

Basic integration gives:
F*t=m(vf-v0),
where vf and v0 are the final and initial velocities of the object respectively.

In your case vf=0, because the ball stops completely, and v0=10m/s.

Rearranging the last expression gives F=(m(vf-vo))/t.

Plug in numbers to find F=(2*10)/0.03=666.6 N

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Answer: buoyancy forceexplanation: in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.