At what distance along the z-axis is the electric field strength a maximum?

The axial field is the integration of the field from each element of charge around the ring. Because of symmetry, the field is only in the direction of the axis. The field from an element ds in the ring is 

dE = (qs*ds)cos(T)/(4*pi*e0)*(x^2 + R^2) 

where x is the distance along the axis from the plane of the ring, R is the radius of the ring, qs is the linear charge density, T is the angle of the field from the x-axis. 

However, cos(T) = x/sqrt(x^2 + R^2) 

so the equation becomes 

dE = (qs*ds)*[x/sqrt(x^2 + R^2)]/(4*pi*e0)*(x^2 + R^2) 

dE =[qs*ds/(4*pi*e0)]*x/(x^2 + R^2)^1.5 

Integrating around the ring you get 

E = (2*pi*R/4*pi*e0)*x/(x^2 + R^2)^1.5 

E = (R/2*e0)*x*(x^2 + R^2)^-1.5 

we differentiate wrt x, the term R/2*e0 is a constant K, and the derivative is 

dE/dx = K*{(x^2 + R^2)^-1.5 +x*[(-1.5)*(x^2 + R^2)^-2.5]*2x} 

dE/dx = K*{(x^2 + R^2)^-1.5 - 3*x^2*(x^2 + R^2)^-2.5} 

to find the maxima set this = 0, giving 

(x^2 + R^2)^-1.5 - 3*x^2*(x^2 + R^2)^-2.5 = 0 

mult both side by (x^2 + R^2)^2.5 to get 

(x^2 + R^2) - 3*x^2 = 0 

-2*x^2 + R^2 = 0 

-2*x^2 = -R^2 

x = (+/-)R/sqrt(2) 

I'm not sure what your asking buddy.. but i know that you can weld two peices of steel by pure force and pressure.