Aball with a mass of 1.5 kilograms is tied to the end of a rope. the ball is pulled to a height of 0.5 meters above the ground and released.

the ball has joules of potential energy at position b. at position a, all of the energy changes to kinetic energy. the velocity of the ball at position a is meters/second. assume there’s no air resistance. use g = 9.8 m/s2 , pe = m × g × h, and

Solve the potential energy at point B

PE = mgh

Where m is the mass

G is the acceleration due to gravity 9.8 m/s2

H is the height

PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

Solve the velocity using the

KE = 0.5mv^2

Where ke is the kinetic energy

M is the mass

V is the velocity

Since all energy is converted to KE

So KE = PE

7.35 = 0.53(1.5) v^2

V = 3.13 m/s

i would say

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle