Your friend drops your house keys down to you from their second floor window. if you catch them 2.4 m from where your friend dropped them, what is the velocity of the keys when you catch them?
a.
-6.9 m/s
c.
-7.2 m/s
b.
-6.5 m/s
d.
-7.4 m/s

V^2=u^2+2as
v^2=0^2+2*9.8*2.4
v^2=47.04
    v=6.9

The answer is -6.8m/s

Apply 3rd equation of kinematics,
v² = u² + 2as
As it is a case of free fall, (u=0), now solve for v,
v² = 0 + 2as
v = √2as

We know, a = -9.8 m/s²
s = 2.4 m

Substitute their values in to the expression,
v = √2*-9.8*2.4
v = √-47.04
v = -6.858 m/s

So, your final answer is 6.858 m/s
By round-off to their nearest tenth, it would be 6.9

So, option A is your answer.
Hope this helps!