Two weather tracking stations are on the equator 159 miles apart. a weather balloon is located on a bearing of n 38°e from the western station and on a bearing of n 14°e from the eastern station. how far is the balloon from the western station?

 A=52 degrees because it is the complementary angle to 38 degrees. 
 B = 104 degrees by adding 90 degrees to the 14 degrees that was given, leaving C to be 24 degrees(180-52-104).

Using the law of Sines
 ⇒ solve for b by cross-multiplying ⇒ b=379.3 miles

4. 50x10= 500m/s 5. 52m/s