The velocity of a particle is described by an equation v= ct + dt^2, where c = 0.1 m/s and d = 0.02 m/s. Calculate:
(i) the change in velocity during the time interval t = 3 seconds and t = 6 seconds.
(ii) the average acceleration in that same time interval​

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What is on your multiple choice anwers

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !