A 1206 kg car accelerates at a rate of 1.7 m/s/s over a distance of 62 meters. How much work was done by the engine on the car?

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Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !

Work is reduced while time is decreased

At maximum height, kinetic energy is converted in potential energy  formula: at max height, ke = ½ * 0.27kg * (16m/s) ² = 34.56 j  so the remaining pe = (41.70 – 34.56)= 7.14 j = 0.27 kg * 9.8m/s² * h  = (9.8/7.14 * 0.27)so max height h = 5.08 or 5 m