A charge of +4.0 C is moved a distance of 0.50 m in a uniform electric field of magnitude 30 N/C. Calculate the work done on this charge by the electric field.

+60 J

Explanation:

Work done by the field on the charge is given by W = qEd where q = charge = +4.0 C, E= electric field strength = 30 N/C and d = distance moved by charge = 0.50 m

So, substituting the values of the variables into the equation, we have

W = qEd

= +4.0 C × 30 N/C × 0.50 m

= +60 Nm

= +60 J

dicrrdirrkdirckrrdrrk ; jhgfdsgrthyjkul; i'lkjhgfdskhjl; jhgdfs