Por un conductor circulan durante 1/4 de hora 54:10 electrones, calcular la intensidad de corriente

whichever one it is, it's definitely not one that you included on the list you provided.

v 154.9= 0.9 length length s little over 154.9cm

0.11 m/s and 0.28 m/s should be correct

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j