Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the 21 cm spectral line corresponding with the flipping of the electron in a hydrogen atom from having its spin parallel to the proton spin to having it antiparallel. From this wavelength, and thus E between states, find the magnetic field experienced by the electron in a hydrogen atom

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

so

Initial potential energy = -μB × cos0°

= -μB × 1

= -μB

Final potential energy = -μB × cos180°

= -μB × -1

= μB

so change in energy will be;

ΔE = μB - ( -μB )

ΔE = 2μB

now, difference in energy levels will be;

ΔE = hc/λ

2μB = hc/λ

2μBλ = hc

B = hc /  2μλ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)]  /  [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ]  /  [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

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explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.

a longitudinal wave moves energy that is to the direction of the wave’s movement. - true