Physics
Physics, 10.04.2021 04:30, acofield975

A potential difference of 25.0 V is applied between the ends of a 30.0-m gold wire with a diameter of 5.50 mm. The resistivity of the wire is 2.44 Γ— 10βˆ’8 Ξ©.m. Calculate
the current in the wire,​

answer
Answers: 1

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A potential difference of 25.0 V is applied between the ends of a 30.0-m gold wire with a diameter...

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