Plz help, will Mark brainliest. A 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V battery. How much current flows out of the battery? (Unit = A)

0.1125A

Explanation:

We need to know the total resistance which will be:

R = R1+R2

where,

R1 = 20 ohm

R2 = 60 ohm

Therefore, R = 20 + 60 = 80 ohm

We should note that from Ohm's law

v = iR

i = v/R

where,

i = 9/80 = 0.1125 A

Therefore, the current that flows out of the battery is 0.1125A

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer