Fig. 1.1 shows a diver working below the surface of a lake. The density of the water in the lake is 1030 kg / m 3 , the atmospheric pressure at the surface is 1.0 × 10 5 Pa and the gravitational field strength is 10 N / kg. The diver inflates a balloon with air at a depth of 25 m and attaches the balloon to a tray of objects. Calculate (i) the pressure due to 25 m of water,

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg