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from 
charge.
charge must be placed in between the two charges to establish equilibrium
cm from 
![\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm](/tpl/images/1246/3628/b09f1.png)
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A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position fo...
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