g Michael and John are playing on a seesaw. Michael has a mass of 25 kg and is sitting to the left, 0.4 m from the center of the seesaw, which is also the center of rotation. John has a mass of 40 kg and is sitting to right of the seesaw. At which distance from the center of the Seesaw should John be sitting so the Seesaw will be in rotational equilibrium (No rotation)? use g=9.8m/s2.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j