A 6.47 micro-coloumb particle moves through a region of space where an electric field of magnitude 1300 N/C points in the positive x direction, and a magnetic field of magnitude 1.33 T points in the positive z direction. If the net force acting on the particle is 6.27E^-3 N in the positive x direction> Required:
Calculate the magnitude of the particle's velocity. Assume the particle's velocity is in the xy plane.

v = 248.8 m/s

Explanation:

Given that,

Charge, q =

Electric field, E = 1300 N/C

Magnetic field, B =1.33 T

The force acting on the particle,

We need to find the magnitude of the particle's velocity. The net force on the particle is given by :

So, the magnitude of the particle's velocity is 248.8 m/s.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

its c its is a mixture of gases