A 1036 nm film with an index of refraction n=2.62 is placed on the surface of glass n=1.52. Light (λ=520.0 nm) falls hits the perpendicular to the surface from air. You want to increase the thickness so the reflected light cancels. What is the minimum thickness of the film that you must add?

Explanation:

= Wavelength falling on film = 520 nm

n = Refractive index of film = 2.62

T = Thickness of film

m = Order

We have the relation

The thickness should be greater than 1036 nm. This means

Thickness of the film to be added would be

Thickness of the film to be added is .

the answer would be 32*f