1. On planet Jupiter, the acceleration due to gravity is about 26 m/s2. How high would a boy
be able to throw a ball on Jupiter if he can
throw it vertically 10m high on Earth?​

The boy can throw the ball to a height of 3.85 m on Jupiter

Explanation:

We'll begin by calculating the initial velocity at which the ball is thrown on EARTH. This can be obtained as follow:

On Earth:

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) = 10 m

Final velocity (v) = 0 m/s (at maximum height)

Initial velocity (u) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – 2 × 10 × 10

0 = u² – 200

Collect like terms

0 + 200 = u²

200 = u²

Take the square root of both side

u = √200 m/s

Finally, we shall determine the maximum height of the ball at JUPITER. This can be obtained as followb

On Jupiter:

Acceleration due to gravity (g) = 26 m/s²

Initial velocity (u) = √200 m/s

Final velocity (v) = 0 m/s (at maximum height)

Maximum height (h) =..?

v² = u² – 2gh (since the ball is going against gravity)

0² = (√200)² – 2 × 26 × h

0 = 200 – 52h

Collect like terms

0 – 200 = –52h

–200 = –52h

Divide both side by –52

h = –200 / –52

h = 3.85 m

Thus, the boy can throw the ball to a height of 3.85 m on Jupiter.

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