How much heat is required to boil 500 grams of water at 100 degrees C if the Hy is 813,700 J/g? Be sure to put the correct units at the end of​

406850000 J

Explanation:

From the question

Q = cm Equation 1

Where Q = Amount of heat, c = latent heat of water, m = mass of water

Given: c = 813700 J/g, m = 500 grams

Substitute these values into equation 1

Q = 500×813700

Q = 406850000 J

Hence the amount of heat requires to boil water at 100°C = 406850000 J

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm