If electromagnetic waves are arranged in increasing order of wavelengths then the order is given as following
1. Gamma rays
2. X rays
3. Ultraviolet waves
4. Visible light
5. Infrared waves
6. micro waves
7. Radio waves
So here we can say that increasing the wavelength means the energy is decreasing as we move towards higher wavelength.
So from above order the larger wavelength with respect to the visible light is given as "Infrared waves"
A). Infrared Radiation
As we know that all electromagnetic waves can propagate without any medium by inducing each other
So here we know that all the electromagnetic waves when arrange in increasing order of energy then
1) Radio Waves
3) Infrared radiations
4) Visible light
5) Ultraviolet radiation
6) X rays
7) Gamma Rays
So we will say that wavelength just more than visible light must have energy just less than visible light
So as per above energy order correct answer will be
A). Infrared Radiations
The correct answer is A and B
Light is part of the spectrum of electromagnetic energy along with radio waves, microwaves, infrared, visible light, ultraviolet, X rays and Gamma rays.
Radio waves and microwaves lie on one end of the spectrum, the longer end of electromagnetic energy.
X rays and Gamma rays have very short wavelengths .
I hope it helps!
im not to sure what it is
c)as speed changes, wavelength and frequency change.