1. A person pulls on a two mass system, connected by a massless string, with a force (FA ) so that the net-acceleration (a) on the system is 7.0 m/s2 down the right slope. The coefficient of friction for the surface m1= 13.0kg is on is k=0.60, while m2= 3.0kg travels along a frictionless surface. m1 = 70 degrees and m2=38.

gravititional force is a force that is acting around you, it is non-contactable and it is a force that pulls you to the core of the earth.

brainliest

it is called kinetic energy

f=ma newton

f=100x2.5=250n

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.