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Physics, 03.02.2020 20:01, jonallere04
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. the equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. when does the object strike the ground?
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Answers: 2
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An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. the equation...
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