Point P is located 1.7 m from fixed point charge q. The electric field Ē at point P is 8.6 x 10-2 N/C, directed away from the point charge. What is the magnitude of q? Let the
electrostatic constant k = 8.99 x 10°N • m²/C2.
O
A. 2.8 10-11 C
0
B. 4.8 * 10-11 C
O. C. -4.8 x 10-11 C
D. 1.5 x 10-10

2.8 × 10^-11 C

Explanation:

The computation of the magnitude of q is shown below;

The electric field at point P because of point charge Q is provided by,

E = 8.6 × 10^-2 N/C

And, the separation between charge Q and P is r = 1.7m

Now According to the Coulomb's law,

E = kQ ÷ r²

8.6 × 10^-2 = 9 × 10^9 × Q ÷ (1.7)²

8.6 × 10^-2 × 2.89 ÷ 9 × 10^9 = Q

Q = (8.6 × 2.89 ÷ 9) × 10^-11

Q = 2.76 × 10^-11 C

= 2.8 × 10^-11 C

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2