A force of 900 N pushes a wedge 0.10 m into a log. If the work done on the log is 50 J, what is the efficiency of the wedge? HEL

55.56%

Explanation:

We'll begin by calculating the work done in pushing the wedge. This can be obtained as follow:

Force (F) = 900 N

Distance (s) = 0.1 m

Workdone (Wd) =..?

Wd = F × s

Wd = 900 × 0.1

Wd = 90 J

Finally, we shall determine the efficiency. This can be obtained as follow:

Work output = 50 J

Work input = 90 J

Efficiency =?

Efficiency = work output / work input

Efficiency = 50 / 90 × 100

Efficiency = 55.56%

Thus, the efficiency is 55.56%

the higher the current the higher the mag field around it the higher the influence on the compass

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft