200 Coulombs of charge passes through a point in a circuit for 0.6 minutes. what is the magnitude of the current flowing​

5.56 A

Explanation:

From the question,

Q = it Equation 1

Where Q = charges, i = current, t = time.

Make i the subject of the equation

i = Q/t Equation 2

Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds

Substitite these values into equation 2

i = 200/(0.6×60)

i = 5.56 A

Hence the magnitude of the current flowing through the circuit is 5.56 A

it should be -8.6 cm hope this out

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.