If the radius of Earth were one half what it is now, and the mass were the same, what would be the value of g?

4 times what it is now.

Explanation:

g=G(M/r^2)

G is constant, so ignore.

We have (1M/0.5r^2), or 4.

4g/9

Explanation:

the equation of g (field gravity)

g = G M/R²

because G (Contant of Gravitasion) and M (Mass of earth) same, them

g2/g1 = R1²/R2²

g1 = g now

g2 = g which the value we looking for

g2/g = 1/(3/2)²

g2/g = 1/(9/4)

g2/g = 4/9

g2 = 4g/9 or we can write ⁴/9 g

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.

b.

hope this : )