Answers: 2
Physics, 22.06.2019 05:00, shimmerandshine1
At time t=0, a particle is located at the point (3,6,9). it travels in a straight line to the point (5,2,7), has speed 8 at (3,6,9) and constant acceleration 2i−4j−2k. find an equation for the position vector of the particle.
Answers: 2
Physics, 22.06.2019 10:30, SauceyNaee
Aparticle moves in the xy plane with constant acceleration. at time zero, the particle is at x = 6 m, y = 8.5 m, and has velocity ~vo = (9 m/s) ˆı + (−2.5 m/s) ˆ . the acceleration is given by ~a = (4.5 m/s 2 ) ˆı + (3 m/s 2 ) ˆ . what is the x component of velocity after 3.5 s? answer in units of m/s.
Answers: 1
Se tienen dos masas m1= 1,2Kg y m2= 2,5Kg, colgando de los extremos de un hilo que pasa por una pole...
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