Physics, 18.03.2021 01:10, hopeR13

Jenny and Anne wanted to see who could throw a ball the hardest. They decided to each throw a ball against a wall as hard as they could and measure how far the ball rolled away from the wall

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answered: yaneli0717

The answer is below

Explanation:

Jenny and anne wanted to see who could throw the ball the hardest. they decided to each throw a ball against the wall as hard as they could and measured how far the ball rolled away from the wall. what might be the variables in this experiment;

Solution:

There are different type of collisions. In an inelastic collision, momentum is conserved and there is loss in kinetic energy while in an elastic collision, momentum is not conserved and there is no loss in kinetic energy.

During inelastic collision, the objects stick together while during an elastic collision, the objects separate.

When the ball is thrown against the stationary wall, there is momentum due to the force of impact. The distance at which the ball is rolled away from the wall depends on:

a) mass of the ball, b) velocity of the ball, c) mass of the wall d) type of collision (elastic or inelastic)

answered: Guest

unbalanced force

explanation:

answered: Guest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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Jenny and Anne wanted to see who could throw a ball the hardest. They decided to each throw a ball a...