A .8 kg block is attached to the end of a spring whose spring constant is 85 N/m. The block is placed on a frictionless tabletop, give an initial displacement of 3.5 cm and then released. What is the magnitude of this energy?​

E = 0.052 J

Explanation:

We are given;

Spring constant; k = 85 N/m

Displacement; x = 3.5 cm = 0.035 m

Formula for the energy is;

E = ½kx²

E = ½ × 85 × 0.035²

E = 0.052 J

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