Forces act on a box that is initially at rest as shown. Coefficient of friction between the object and the surface is μ=0.1. If the box' mass is 6kg box and if it is moving with acceleration of 0.4m/s2, what distance will the box travel if it was pushed for 4s?

3.2 m

Explanation:

From the question given above, the following data were obtained:

Coefficient of friction (μ) = 0.1

Initial velocity (u) = 0 m/s

Mass (m) = 6 Kg

Acceleration (a) = 0.4 m/s²

Time (t) = 4 s

Distance (s) =.?

The distance travelled can be obtained as illustrated below:

s = ut + ½at²

s = (0×4) + (½ × 0.4 × 4²)

s = 0 + (0.2 × 16)

s = 0 + 3.2

s = 3.2 m

Thus, the box will travel 3.2 m in 4 s.

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