A particle with an initial linear momentum of 2.00 kg-m/s directed along the positive x-axis collides with asecond particle, which has an initial linear momentum of4.00 kg-m/s, directed along the positive y-axis. The finalmomentum of the first particle is 3.00 kg-m/s, directed45.0?Above the positive x-axis. Find the final momen -tum of the second particle.

Explanation:

We shall apply conservation of momentum along x and y axis.

Let the final momentum of second particle be p₁ along x axis and p₂ along y axis.

Considering momentum along x axis

2 + 0 = 3 cos 45 + p₁

p₁ = 2-2.12 = - 0.12 kg m/s

Considering momentum along y axis

4 + 0 = 3 sin 45 + p₂

p₂ = 4-2.12 = 1.88  kg m/s

Final momentum = √ ( p₁² + p₂² )

=√ ( .12² + 1.88² )

= 1.88 approx

im sorry i dont know

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles