Vertically polarized light with an intensity of (763 A) W/m2 passes through two polarizing filters. The first filter is rotated at an angle of (13.5 B) degrees from the vertical and the second filter is aligned with the horizontal. Find the intensity of the light after passing through the two polarizing filters. Give your answer in W/m2 as the original light and with 3 significant figures.

I = 176 W / m²

Explanation:

To solve this exercise let's use Malus's law

          I = I₀ cos² θ

where tea is the angle between the plane of polarization of the light and the axis of the polarizer

let's apply this equation, the light has vertical polarization and the axis of the polarizer is at θ₁= 13.5º, we measure atoms the angles with respect to the vertical

          I₁ = I₀ cos² tea

          I₁ = 763 cos² 13.5

          I₁ = 741.92 w / m²

when it reaches the second polarizer the angle is

           θ₂ = 13.5 - 90

           θ₂ = - 76.5º

           I₂ = I₁ cos² θ₂

           I₂ = 741.92 cos² 76.5

           I₂ = 176.2 W / m²

applying the criterion of significant figures

          I = 176 W / m²

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .