An athlete whirls a 7.00 kg hammer 1.8 m from the axis of rotation in a horizontal circle, as shown in the figure below. The hammer makes one revolution in 1.0 s. What is the tension in
the chain?

A-500 N
B-50 N
C-5000 N
D-5 N

A-500 N

Explanation:

The computation of the tension in the chain is shown below

As we know that

F = ma

where

F denotes force

m denotes mass = 7

And, a denotes acceleration

Now for the acceleration we have to do the following calculations

The speed (v) of the hammer is

v = Angular speed × radius

where,

Angular seed = 2 × π ÷ Time Period

So, v = 2 × π × r ÷ P

v = 2 × 3.14 × 1.8 ÷ 1

= 11.304 m/s

Now

a = v^2 ÷ r

= 70.98912 m/s^2

Now the tension is  

T = F = m × a

= 7 × 70.98912

= 496.92384 N

= 500 N

the closer the planet is to the sun, the larger the gravity