Activity 2 forces
1
Two forces act on an object. The first is a horizontal 50 N force. The
second is a 40 N force acting at an angle to the horizontal.
1.1 Use a graphical method drawn to a scale of 1 mm: 1 N to find the
resultant if the 40 N force is inclined at:
1.1.1 30° to the horizontal
1.1.2 60° to the horizontal.
.2 Compare the resultant forces and make a generalisation after answering
the following question. Does the magnitude of the resultant of two
vectors increase, stay the same or decrease when the angle between the
vectors increases?
3 Consider and then state the angle (in degrees) between two vectors for
which the magnitude of their resultant is:
1.3.1 smallest
1.3.2 largest
Figures 4 and 5 show forces that act in the
vertical plane on an object.
Determine the resultant of the forces in each
diagram by means of a graphical method.
up
56:30°5N
1​

sorry I can't answer this

answer; equivalent to a one(1) horsepower motor;

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.