Question 2 (1 point) ✓ Saved (3.03.b_Q2) NOTE: The same story problem is used for questions 1 - 5: In a
piston/cyclinder gas container, the piston starts with a inside gas volume of 3.0 cc
and a pressure of 0.8 atmosphere at room temp. The piston is pushed into the
cylinder, reducing the volume to 1.0 cc. The piston/cylinder is left to equilibrate
back to room temp before measuring the final pressure.
Which gas law formula should be used to solve this opportunity?
constant volume, initial P/T = final P/T
constant temperature, initial PV = final PV
constant pressure, initial V/T = final V/T
density = mass/volume

The gas law formula that should be used to solve the opportunity is;

Constant temperature, initial P·V = final P·V

Explanation:

From the question we have;

The initial volume of the cylinder, v₁ = 3.0 cc

The initial pressure of the gas in the cylinder, p₁ = 0.8 atm

The initial temperature of the gas in the cylinder, T₁ = Room temperature

The final volume of the cylinder, v₂ = 1.0 cc

The final pressure of the gas in the cylinder = p₂

The final temperature of the gas in the cylinder, T₂ = Room temperature

The gas law formula that should be used to solve the opportunity is Boyle's law which states that at constant pressure the pressure, of a given mass of gas is inversely proportional to the volume of the gas

Mathematically, Boyle's law can be expressed as follows;

P ∝ V

∴ P₁·V₁ = P₂·V₂

Which gives;

Constant temperature, initial P·V = final P·V

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

a and c

c is 100% but i am confused in a