If the distance between 2 charged particles is double, the force between them changes by a factor of?

See explanation

Explanation:

Given that;

q1 and q2 are the magnitudes of the two charges while r1 is the distance between the charges.

F1 =kq1q2/r1^2

Then,

F2 = kq1q2/(2r1)^2

F2 = kq1q2/4r1^2

So,

F2 = 1/4 F1

The force between the charges changes by a factor of 1/4.

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!