A runner runs 480 m towards north on a straight track in 120 s and then walks back the same distance in 300 s. (Note: velocity and speed are two different physical quantities) (a) What is the average velocity for the first part of the motion?

(b) What is the average velocity for the second part (walking back) of the motion?

(c) Calculate his average velocity for the entire motion.

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This is kenetic energy.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.