A 5.0 kg bowling ball is sitting on a rack and its gravitational potential energy is 74 J. How high is the bowling ball above the floor? GIVE WORK

Actually Welcome to the Concept of the Work, energy and power.

Potential energy = m*g*h, here g = 9.8 m/s^2 (universal value)

hence, h = P/m*g

==> h = 74/ 5*9.8

===> h = 74/49

==> h = 1.51 meters

hence the height is 1.51 m

be subject to a force andchange its motion

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west