A large artery in a dog has an inner radius of 4×10^–3 m blood flows through the artery at the rate of 1×10^–6 m^3 s^–1 the blood has a viscosity of 2.084 ×10^–3 pa. s and a density of 1.06×10^3 kgm^–3 calculate the average blood velocity in the artery​

Bag of bolts weight 29.4n

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

The upward force acting on the wing of a airplane in flight is known as the "lift" force. (d)