A mass of 0.55kg attached to a vertical spring stretches it by 0.36m Calculate the spring constant of the spring. Take the gravitational field strength to be 10N/kg

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

answer( sicar );